What Are You Waiting For?
Sign In or Sign Up Now to begin your journey with us!
Tweet
Invite your friends now. the more the merrier! Invite your friend to connect with each other.
:: Movie Contest Update ::
This contest has been closed.
Sign in or sign up
now to tell your friend about your referrer ID for use upon their registration. Cheers.
Weekly movie voucher contest is closed.
Maberlee weekly movie voucher contest is ended. Last pair of movie vouchers have been given out.
Read more
View past contest winners
nisha sharma
added a new attachment:
kindly resolve....
WhatsApp Image 2017-06-14 at 11.17.09 AM.jpeg
1 reply
0 like
0 share
June 14, 2017 at 6:17am
Little Sky
:
[deqn]f(z)=\text{quotient}\times\text{divisor}+\text{remainder}[/deqn] For case [ieqn]f(z)=az^3+4z^2+3z-4=\text{quotient_1}\times(z-3)+\text{common remainder}[/ieqn] For case [ieqn]f(z)=z^3-4z-a=\text{quotient_2}\times(z-3)+\text{common remainder}[/ieqn] You should observe that for both cases, when z = 3, you are left with the common remainder. For 1st case, [ieqn]f(3)=a(3)^3+4(3)^2+3(3)-4=27a+36+9-4=27a+41[/ieqn] For 2nd case, [ieqn]f(3)=3^3-4(3)-a=15-a[/ieqn] By equating the remainder 27a + 41 and 15 - a, you should get a = -26/28
0 like
June 14, 2017 at 7:16am
Sign In or Sign Up
to reply to this post.
© 2019
Maberlee
. All rights reserved. A Chong Tian En production.